4x^2-37x+48=-8x+3

Solution for 4x^2-37x+48=-8x+3 equation:

4x^2-37x+48=-8x+3

We move all terms to the left:

4x^2-37x+48-(-8x+3)=0

We get rid of parentheses

4x^2-37x+8x-3+48=0

We add all the numbers together, and all the variables

4x^2-29x+45=0

a = 4; b = -29; c = +45;
Δ = b2-4ac
Δ = -292-4·4·45
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-11}{2*4}=\frac{18}{8}
=2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+11}{2*4}=\frac{40}{8}
=5
$